what is the formula for gpe?Do youMultiply?
ms. James for the ecology project can it only be one thing because i wanted to do it on reducing carbon footprint so can i do like recycling and other things on can it only be one thing
@ ScottieGPE= mgh or GPE= whw= mgg= 9.81 m/s^2@SydneyI am not sure if I understand, but yes your project can be only one thing
Ms.james on ex. 6-3 how did you get 1.24
[ms. james, on the other website(allaboutabearandabug) i comented saying, i dont know what topic/ so i will ask it here......] I dont have any other ideas for the ecology project? do you have any examples? and also, when is the journal entry due...?
@ScottieHow much mass energy, in joules, could be obtained from the complete conversion of a compact 138 g media player?m= 138 g You have to convert to kg here m= 0.138 kgc= 3.00 x 10^8 m/ssince c is squared c^2= 9 x 10^16 m^2/s^2E= ?E= mc^2E= 0.138 kg (3.00 x 108 m/s)2E= 0.138 kg (9 x 10^16 m^2/s^2)E= 1.242 x 10^16 kg* m2/s2E= 1.24 x 10^16 Jthe carrot (^) indicates that you have to make the number that follows a superscript (10^16 means 10 to the 16th power)Let me know if this helps
Ciara, there are many things to do. Talk to me in homeroom and I will give you some ideas. BTW the eco-blog is not for class questions, I want to keep it strictly eco-info
ok ms.james after you goto.138kg(9x10^16m^2/s^)what do you do because i dontunderstand where you got 1.242
@Scottie, after you square c (3.0 x 10^8 m/s) you multiply it by 0.138 kg. that is 9 x 10^16 m^2/s^2so you can actually just multiply 0.138 kg by 9 and you will get 1.24 then just add the x 10^16 m^2/s^2 and you will have 1.24 x 10^16 kg m^2/s^2
how do u use e=mc2
Hey. Ms. J If we use the notes that you told us to write down will that suffice for the test or should we study the book and notes. My second question is what formulas do we have to know?
can u give me an exampel and explan it
ms.james can you please send me2 examples of gpe and e=m2 so i can seesee if i get them correct
@ scottie you are welcomeScottie and Jeremiah, I have worked our some problems below. I will attach some problems to today's post.How much gravitational potential energy has a boy whose mass is 50 kg and who is standing on top of a 1.5 meter high wall?GPE= mghm= 50 kgg= 9.81 m/s^2h= 1.5 mGPE= (50 kg)(9.81 m/s^2)(1.5 m)GPE= 735.75 kg m^2/s^2GPE= 735 JHow much energy would be generated if a physics student (mass = 62 kg) could be completely turned into energy?E= mc^2E=?m= 62 kgc= 3.0 x 10^8 m/sc^2= 9.0 x 10^16 m^2/s^2E= 62 kg(9.0 x10^16 m^2/s^2)E= 558 x 10^16 k m^2/s^2E= 558 x 10^16 JE= 5.58 x10^18 J
Hi,Mrs. James i wanted to know what was the homework was for today.